Answer:
concentration of glucose = 78.75 mg/dL
Step-by-step explanation:
The question essentially wants to test the ability to calculate the concentration of a patient's test result done on a spectrophotometer using the absorbance from Beer-Lambert's law, which states that when incident light passes through a medium, the absorbance is directly proportional to the concentration of the medium and inversely to the length of the light path.
Mathematically it is represented as
Absorbance (A) ∝ Concentration (C) (or length of path)
A ∝ C
A = kC
where "k" represents the factors that are kept constant.
As a result we can rewrite the formula as:
A₁ = C₁ - - - - - (1)
A₂ = C₂ - - - - -(2)
And dividing both equations:
Next, let us define what is "standard" is; in analytical chemistry, a standard solution is one containing a precisely known concentration of the analyte in question, and it can be applied into the Beer-Lamberts law as follows: