Answer:
[HClO₄] = 0.35 M
Step-by-step explanation:
Neutralization reaction is:
HClO₄ + LiOH → LiClO₄ + H₂O
In this case, we have a titration between a weak acid and a strong base.
In chemistry it is also called an acid base equilibrium.
HClO₄ + H₂O ⇄ ClO₄⁻ + H₃O⁺ Ka
The weak acid is firstly neutralized by the strong base, in order to have a buffer solution before the equivalence point.
When we reach the equivalence point, mmoles of acid = mmoles of base and there is a formula to determine it so:
M acid . Volume of acid = M base . Volume of base
M acid . 100 mL = 0.75 M . 46.9 mL
M acid = (0.75 M . 46.9 mL) / 100 mL → 0.35 M