Question

Find the equation of the line.
Through (-8,11); perpendicular to y=9

Answer 1

• Perpendicular to y=9
• Slope is 0

Perpendicular lines have slope negative reciprocal to each other .

• -1/0=oo

Equation of line in point slope form

`\\ \rm\Rrightarrow y-y_1=m(x-x_1)`

`\\ \rm\Rrightarrow y-11=\infty(x+8)`

`\\ \rm\Rrightarrow (y-11)/(\infty)=x+8`

`\\ \rm\Rrightarrow x+8=0`

`\\ \rm\Rrightarrow x=-8`

Some formats of line

`\boxed{\begin{array}c\boxed{\bf Form} &\boxed{\bf Equation} \\ \sf Slope\: intercept\:form &\sf y=mx+b \\ \sf Intercept\:form &\sf (x)/(a)+(y)/(b)=1\\ \sf Normal\:form &\sf xcos\omega+ysin\omega=p \\ \sf Two\: point\:form &\sf y-y_1=\left((y_2-y_1)/(x_2-x_1)\right)(x-x_1)\\ \sf Point\:slope\:form &\sf y-y_1=m(x-x_1) \\ \sf Standard\:form &\sf Ax+By+C=0 \end{array}}`