Question

Pls help and neatly show work

Answer 1

Explanation:

a

(x+5)(2x+7)-(x+5)(x-3)

factorize (x+5) out

(x+5)[(2x+7)-(x-3)]

(x+5)(2x+7-x+3)

(x+5)(2x-x+7+3)

(x+5)(x+10)

b. to get the zeros of the equation,

(x+5)(x+10)=0

x+10=0

x=-10

since the other one has been found already

Answer 2

Explanation:

(2x^2 + 10x + 7x + 35) - (x^2 - 3x + 5x - 15)

x^2 + 15x + 50

(x + 5)(x + 10)

x = -10