1 Answer

Tkazik · Answer 1 · 2022-10-15T12:21:33+0000

Answer: 10 s, 30 m/s , 150 m

Step-by-step explanation:

Given

The speed of motorcyclist is
$u_1=15\ m/s$

The initial speed of a police motorcycle is
$u_2=0\ m/s$

acceleration of police motorcycle is
$a=3\ m/s^2$

Police will catch the motorcyclist when they traveled equal distances

distance traveled by motorcyclist in time t is

$\Rightarrow s_1=15* t$

Distance traveled by Police in time t is

$\Rightarrow s_2=u_2t+(1)/(2)at^2\\\Rightarrow s_2=0+0.5* 3* t^2$

put
s_1=s_2

$\Rightarrow 15t=0.5* 3* t^2\\\\\Rightarrow t(1.5t-15)=0\\\\\Rightarrow t=(15)/(1.5)=10\ s$

Police officer's speed at that time is

$\Rightarrow v_2=u_2+at\\\Rightarrow v_2=0+3* 10=30\ m/s$

Distance traveled by each vehicle is

$\Rightarrow s_1=s_2=15* t=15* 10=150\ m$

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