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If AC is the perpendicular bisector of BD and BD is the perpendicular bisector of AC, then how is triangle APB congruent to triangle CPB?
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If AC is the perpendicular bisector of BD and BD is the perpendicular bisector of AC, then how is triangle APB congruent to triangle CPB?

If AC is the perpendicular bisector of BD and BD is the perpendicular bisector of-example-1
User Marwan Salim
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1 Answer

5 votes

Answer:

AB=BC

4X-1=1+2x so x=1 and both sides are 3

Explanation:

since bd is a perpendicular bisector the two triangles formed are congruent so AB=BC

4X-1=1+2x so x=1 and both sides are 3

User Dmitry F
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