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What is the molality of a solution that contains 435 grams of Fe(ClO 2 3)3 , in 750.0 g of solvent?

User Nathan Totura
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1 Answer

11 votes
11 votes

Answer:

2.24 M

Step-by-step explanation:

Molality is a measure of molar concentration of a solution and it can be calculated using the formula;

Molality = mole of solute ÷ kg of solvent

To calculate the number of moles present in the solute, we use the formula;

mole = mass ÷ molar mass

Molar mass of Fe(ClO2)3 = 56 + {35.5 + 16(2)}3

= 56 + (35.5 + 32)3

= 56 + (67.5)3

= 56 + 202.5

= 258.5g/mol

mole = 435/258.5

mole of Fe(ClO2)3 = 1.68mol

750g of solvent = 750/1000 = 0.750kg of solvent

Molality of the solution is thus: 1.68/0.750

Molality = 2.24 M.

User Nick Vikeras
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