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7.5 g CaCl2.9H2O (1 mol / 273.1215 g) ( 1 mol CaCl2 / 1 mol CaCl2.9H2O ) ( 110.98 g / 1 mol ) =

7.5 g CaCl2.9H2O (1 mol / 273.1215 g) ( 1 mol CaCl2 / 1 mol CaCl2.9H2O ) ( 110.98 g / 1 mol ) =
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7.5 g CaCl2.9H2O (1 mol / 273.1215 g) ( 1 mol CaCl2 / 1 mol CaCl2.9H2O ) ( 110.98 g / 1 mol ) =

User Petek
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Use Socratic or mathpapa
User Anthony Griggs
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Determine the quantity (g) of pure CaCl2 in 7.5 g of CaCl2•9H2O
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