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23 votes
23 votes
the electrostatic force between two objects is 40N. if the charge of one object is cut in half, and the distance is doubled, what is the new force?

User Shakisha
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1 Answer

18 votes
18 votes

Answer:

F1 = K Q1 Q2 / R1^2

F2 = K Q1 / 2 * Q2 / (2 R1)^2

F2 / F1 = 1/2 / 4 = 1/8

The new force is 5N (1/2 due to charge and 1/4 due to distance)

User Farrukh Waheed
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