Answer:
It is possible to find the zero and f(x).
Other zero is (2, 0).
f(x) = -x(x - 2).
Explanation:
As one of the zeroes is at (0,0) the function will be of the form:
y = -ax(x - b) where b = the other zero and a is a constant.
The negative coefficient is there because the quadratic has a maximum value as it opens downwards.
As the curve is symmetric about x = 1 ( because the vertex is at 1,1) the second zero is at (2, 0). So b = 2.
As the vertex is at (1, 1) the value of a is also 1.