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26 votes
26 votes
What is the Ka of a 0.0592 M solution of hydrofluoric acid (HF) with a pH of 6.90

User Ezpz
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2 Answers

21 votes
21 votes

Answer: 2.7 x 10^-13

Step-by-step explanation:

User Dryniex
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3.3k points
12 votes
12 votes

Answer:

2.7*10^-13

coefficient= 2.7

exponent= -13

Step-by-step explanation:

User Prajmus
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3.4k points