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If (x+1),6x,48,192 are in proportion,find the value of x

User Vlad Turak
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1 Answer

1 vote

Answer:

the value of x is 2

Explanation:

The computation of the value of x is shown below:

a:b = c:d

where

a = x + 1

b = 6x

c = 48

d = 192

Now


(x+1)/(6x) = (48)/(192) \\\\(x+1)/(6x) = (1)/(4)\\\\4x + 4 = 6x\\\\4 = 6x - 4x\\\\4 = 2x\\\\x = (4)/(2)\\\\x = 2

Hence, the value of x is 2

Therefore the same would be considered and relevant too

User Gaperton
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