Answer:
A. Area of ABCD = 240
![cm^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/rh1gjq8uygmsrcxnmtgq7j282r77jlctve.png)
B. 60 cm
C. 36 cm
D. 50 cm
Explanation:
Given: AB = 24cm BC = 10cm and AE = 13cm.
A. Since a rectangle is a 2 dimensional figure, it has no volume but area.
So that,
the area of the rectangle ABCD = length x width
= 24 x 10
= 240
![cm^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/rh1gjq8uygmsrcxnmtgq7j282r77jlctve.png)
B. To calculate the circumference of the BCD triangle, apply the Pythagoras theorem to determine BD.
=
+
![DC^(2)](https://img.qammunity.org/2022/formulas/mathematics/college/jg191jomdfikzeqaqx876maox3b8bdhwh3.png)
=
+
![24^(2)](https://img.qammunity.org/2022/formulas/engineering/college/7pua1ekzwwyrjudsdppwxtn917cvpy25w4.png)
= 676
BD =
![√(676)](https://img.qammunity.org/2022/formulas/mathematics/high-school/abdmfhhnqrgfzk4dahx43gg92ud3xpbmnt.png)
= 26
BD = 26 cm
so that,
the circumference of BCD = 10 + 24 + 26
= 60 cm
C. To calculate the circumference of the BEC triangle,
AC = 26 cm, AE = 13 cm
CE = 26 - 13
= 13 cm
CE = 13 cm
The circumference of the BEC triangle = 13 + 13 + 10
= 36 cm
D. The circumference of the DEC triangle = 13 + 13 + 24
= 50 cm