Answer:
-11.
Explanation:
f(x) = √(3 - 2x), x ≤ 3/2
let y = √(3 - 2x)
y^2 = 3 - 2x
2x = 3 - y^2
x = (3 - y^2)/2
So f-1(x) = (3 - x^2)/2
f-1(x) = (3 - 5^2) / 2 = -11.
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