Question

Write the polynomial in factored form as a product of linear factors:

p(a) = a^3 + 3a^2+ 9a + 27
zeros of polynomial.

Answer 1

Explanation:

p(A) = a^3 + 3a^2 + 9a + 27

put brackets around the 1st and second terms and another set around the 3rd and 4th

P(a)= (a^3 + 3a^2) + (9a + 27)

Using the distributive property, pull out the common factor for each of the 2 terms that contain the brackets.

P(a) = a^2 ( a + 3) + 9(a + 3)

Let a + 3 = x

P(a) = a^2x + 9x

Put brackets around these 2 terms

P(a)= x(a^2 + 9)

Substitute a + 3 for x

P(a) = (a + 3) ( a^2 + 9)