Question

37.4 g of aluminum chloride reacts with bromine gas to yield aluminum bromide and chlorine gas. How many liters of bromine gas is needed to completely react with aluminum chloride? Assume both gases are at STP.

Answer 1

9.43 L Br₂ (g)

Step-by-step explanation:

First, write a balanced reaction equation. Then use dimensional analysis to convert from grams of aluminum chloride to moles of aluminum chloride (with molar mass from the periodic table), from moles of aluminum chloride to moles of bromine gas (using the balanced equation), and from moles of bromine gas to liters of bromine gas (remember at STP, 1 mol = 22.4 L). See the attached image for the work out. Finally, account for sig figs to get 9.43 L of bromine gas