Question

A 250 mL beaker is submerged in a large container of Liquid X and turned upside down, and another 250 mL beaker is submerged and turned upside down in a large container of Liquid Y. Hydrogen (H2) gas is bubbled into each upside-down beaker until 100 mL of liquid has been displaced. The masses m X and my of hydrogen inside each beaker is then chemically determined.

a. mx will be greater than my
b. m x will be less than my
c. mx will be equal to my
d. It's impossible to predict whether mx or my will be greater without more information.

Answer 1

Mx will be less than My.

Step-by-step explanation:

The correct option is - Mx will be less than My.

Because, liquid X have been higher viscosity and vapor pressure than liquid B.

Vapor pressure of liquid A is greater, so the amount of liquid X will vaporized greater and H2 gas has been displaced greater from the beaker as compared to liquid Y.

The amount of H2 in liquid Y remains greater in beaker as compared to liquid X.

So, Mx will be less than My.