Question

Particles q₁ = +9.33 µC, q₂ = +4.22 µC, and 93 = -8.42 µC are in a line. Particles q₁ and q₂ are separated by 0.180 m and particles q₂ and q3 are separated by 0.230 m. What is the net force on particle q₂? Please help up to 100 points.​

Answer 1

Fnet = 16.98204316 N will point right

Step-by-step explanation:

q₁ and q₂ both positive ⇒ F₁₂ will point right, repel

q₂ pos and q₃ neg ⇒ F₂₃ will point right, attract

Fnet = F₁₂ + F₂₃

Fnet = k.q₁.q₂/r₁₂² + k.q₂.q₃/r₂₃²

Fnet = 9x10⁹x 9.33x10⁻⁶x4.22x10⁻⁶/(0.18)² + 9x10⁹x 4.22x10⁻⁶x8.42x10⁻⁶/(0.23)²

Fnet = 0.3543534/(0.18)² + 0.3197916/(0.23)²

Fnet = 10.93683333 + 6.04520983

Fnet = 16.98204316 N