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2 votes
9 mol P4010 reacts with 51 mol

H₂O according to the equation below:
P4010 + 6H₂O → 4H3PO4
How many moles of H3PO4 form
from 51 mol H₂O?
[?] mol H3PO4
Round your answer to the ones place.
HELP ASAP WORTH LOTS OF POINTS

9 mol P4010 reacts with 51 mol H₂O according to the equation below: P4010 + 6H₂O → 4H-example-1

2 Answers

3 votes

Answer:

It's 36

Step-by-step explanation:

6 x 6 = 36

User Empz
by
5.1k points
0 votes

Using stoichiometric relationships:


P_4O_1_0 + 6H_20
4H_3PO_4

moles P4O10 = 9 mol

mol H2O = 51 mol/6

mol H2O = 8.5

H2O is limiting


51molsH_2O x
(4 mol H_3PO_4)/(6 molH_2O)

∴ moles H3PO4 = 34 mol

User Jason Dancks
by
5.4k points