Answer:
161.938 Hz
Step-by-step explanation:
the computation of the fundamental resonant frequency is shown below
p = 1100 kg/m^3
A = 130 mm^2
= 130 ×10^-6 m^2
T = 600 N
L = 20 cm
= 0.2 m
Now the linear density of tendon is
= 1100 kg/m^3 × 130 ×10^-6
= 0.143 kg/m
Now the wave of the string is
= √600 ÷ √0.143
= 64.775 m/s
Now finally the fundamental resonant frequency is
= 64.775 ÷ (2 × 0.2)
=161.938 Hz