Question

17

If 225 grams of water is to be heated from 25.0°C to 100.0°C to make a cu
tea, how much heat must be added? The specific heat of water is 4.18 J/g.
(5 Points)
63536)
70538)
117562)
705)

Answer 1

Heat energy required (Q) = 70,537.5 J

Step-by-step explanation:

Given:

Mass of water (m) = 225 grams

Initial temperature of water = 25.0°C

Final temperature of water = 100.0°C

Specific heat of water (c) = 4.18 J/g

Find:

Heat energy required (Q)

Computation:

Change in temperature Δt = Final temperature of water - Initial temperature of water

Change in temperature Δt = 100 - 25

Change in temperature Δt = 75°C

Using Heat energy formula

Q = (m)(c)(Δt)

Heat energy required (Q) = (225)(4.18)(75)

Heat energy required (Q) = 70,537.5 J