Answer:
In pass-by-value, the function receives a copy of the argument as a parameter. This means that any changes made to the parameter inside the function have no effect on the argument outside the function.
On the other hand, in pass-by-reference, the function receives a reference to the memory location of the argument. This means that any changes made to the parameter inside the function are reflected in the argument outside the function.
Here is an example in C++ to illustrate the difference:
#include <iostream>
void increment(int x)
{
x++;
}
void increment(int* x)
{
(*x)++;
}
int main()
{
int y = 5;
increment(y); // pass-by-value
std::cout << y << std::endl; // prints 5
increment(&y); // pass-by-reference
std::cout << y << std::endl; // prints 6
retuIn the first call to increment, the value of y is passed to the function as a parameter. Since the function receives a copy of the value of y, any changes made to the parameter inside the function have no effect on the argument outside the function. Therefore, the value of y is not changed and remains 5.
In the second call to increment, the memory address of y is passed to the function as a parameter. Since the function receives a reference to the memory location of y, any changes made to the parameter inside the function are reflected in the argument outside the function. Therefore, the value of y is incremented to 6.rn 0;
}
Step-by-step explanation: