Answer:
The expected value for the number of defects on a randomly selected plastic part is 0.43.
Explanation:
We have the following probability distribution:
P(X = 0) = 0.79
P(X = 1) = 0.09
P(X = 2) = 0.05
P(X = 3) = 0.04
P(X = 4) = 0.03
What is the expected value, E(X), for the number of defects on a randomly selected plastic part?
Each value multiplied by its probability. So
The expected value for the number of defects on a randomly selected plastic part is 0.43.