Answer:
sodium pentanoate and ethylmethylamine
Step-by-step explanation:
The reaction of N,N-ethylmethylpentanamide with sodium hydroxide involves an amide and an inorganic hydroxide.
The CO-N bond is highly polar hence the -N(C2H5) (CH3) moiety is easily lost and replaced by the -ONa leading to the formation of sodium pentanoate.
The H^+ combines with -N(C2H5) (CH3) to yield ethylmethylamine