Answer:
Therefore, Alvin worked 70 hours, Simon worked 55 hours, and Theodore worked 159 hours
Explanation:
Let A be the number of hours Alvin worked, S be the number of hours Simon worked, and T be the number of hours Theodore worked.
We know that the total number of hours worked is the sum of the hours each person worked, so we can write the equation:A + S + T = 284
We also know that Alvin worked 15 more hours than Simon, so we can write the equation:A = S + 15
We also know that Theodore worked 6 less than three times as many hours as Simon, so we can write the equation:T = 3S - 6
Substituting the second equation into the first equation, we get:
S + S + 15 + 3S - 6 = 284
Combining like terms, we get:5S + 9 = 284
Subtracting 9 from both sides, we get:5S = 275
Dividing both sides by 5, we get:S = 55
Substituting this value into the equation A = S + 15, we get:
A = 55 + 15A = 70
Substituting this value into the equation T = 3S - 6, we get:T = 3 * 55 - 6T = 165 - 6T = 159