Answer:
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Explanation:
To find the slope and y-intercept of the equation 3x + √3y = 6, we can first rearrange the equation into slope-intercept form. In slope-intercept form, the equation of a line has the form y = mx + b, where m is the slope and b is the y-intercept.
To rearrange the equation 3x + √3y = 6 into slope-intercept form, we can solve for y:
3x + √3y = 6
√3y = -3x + 6
y = (-3x + 6)/√3
The slope of the line is m = -3/√3 = -√3, and the y-intercept is b = 6/√3. Therefore, the slope-intercept form of the equation is y = -√3x + 6/√3.
The slope of the line is the rate at which the y-value changes as the x-value changes. In this case, the slope is -√3, which means that for every 1 unit change in the x-value, the y-value changes by -√3 units.
The y-intercept is the point at which the line crosses the y-axis. In this case, the y-intercept is (0, 6/√3), which means that the line crosses the y-axis at y = 6/√3.