Answer:
Mr. Abyad used a total of 10 3/12 square feet of material
Explanation:
To solve this problem, we need to add the amounts of material that Mr. Abyad used for each of the bulletin boards.
The first bulletin board used 3 2/3 square feet of material, which is equal to 3 + 2/3 square feet.
The second bulletin board used 6 3/4 square feet of material, which is equal to 6 + 3/4 square feet.
The third bulletin board used 4 1/3 square feet of material, which is equal to 4 + 1/3 square feet.
To find the total amount of material that Mr. Abyad used, we need to add these three quantities:
3 + 2/3 + 6 + 3/4 + 4 + 1/3 = 13 + 9/12 + 5/4 = 13 + 5/4 + 9/12
We can't add these fractions directly, so we need to find a common denominator. The least common multiple of 3, 4, and 12 is 12, so we can use that as the common denominator.
We can rewrite 13 + 5/4 as 13 + 5/4 * 3/3, which is equal to 13 + 15/12.
We can rewrite 9/12 as 9/12 * 4/4, which is equal to 3/3.
Adding these quantities gives us:
13 + 15/12 + 3/3 = 13 + 15/12 + 12/12 = 13 + 15 + 12/12 = 28/12 + 12/12 = 40/12 = 10 3/12
Therefore, Mr. Abyad used a total of 10 3/12 square feet of material.