Answer:
The equation of the line that passes through the point (-6, -7) and has a slope of 1/3 is:
x - 3y + 15 = 0
Explanation:
The equation of a line in slope-intercept form is given by y = mx + b, where m is the slope of the line and b is the y-intercept (the point at which the line crosses the y-axis).
To find the equation of the line that passes through the point (-6, -7) and has a slope of 1/3, we can use the point-slope form of a line:
y - y1 = m(x - x1)
Where (x1, y1) is a point on the line and m is the slope of the line.
Plugging in the given values, we have:
y - (-7) = (1/3)(x - (-6))
Which simplifies to:
y + 7 = (1/3)x + 2
Multiplying both sides by 3, we have:
3y + 21 = x + 6
Subtracting 21 and 6 from both sides, we have:
3y - x - 15 = 0
Therefore, the equation of the line that passes through the point (-6, -7) and has a slope of 1/3 is:
x - 3y + 15 = 0