\dfrac12(10x + 20y +10z) = 2 1 (10x+20y+10z)=start fraction, 1, divided by, 2, end fraction, left parenthesis, 10, x, plus, 20, y, plus, 10, z, right parenthesis, equals

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Ed Avis asked Jan 1, 2022

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\dfrac12(10x + 20y +10z) = 2 1 (10x+20y+10z)=start fraction, 1, divided by, 2, end fraction, left parenthesis, 10, x, plus, 20, y, plus, 10, z, right parenthesis, equals

Mathematics
high-school

Ed Avis asked Jan 1, 2022

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Answer:

5x + 10y + 5z

Explanation:

Given the expression

Expand the parenthesis using the distributive law;

Hence the required solution is 5x + 10y + 5z

Hyung answered Jan 8, 2022

by Hyung

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