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Suppose you have the following circuit diagram. Here R1=22kΩ, R2=33kΩ, R3=1.1kΩ, R4=3.3kΩ, R5=33kΩ, R6=11kΩ, R7=33kΩ, R8=1.1kΩ, R9= 3.3kΩ are the resistances on the circuit where kΩ stands for kilo ohm.
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Suppose you have the following circuit diagram.

Here R1=22kΩ, R2=33kΩ, R3=1.1kΩ, R4=3.3kΩ, R5=33kΩ, R6=11kΩ, R7=33kΩ, R8=1.1kΩ, R9=
3.3kΩ are the resistances on the circuit where kΩ stands for kilo ohm. The electromotive forces
of the batteries are E1=3volts and E2=6volts.

User Bogdan
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4.8k points

1 Answer

3 votes

Answer:

The current I1 through the resistor R1 is:

I1 = (E1 - E2) / (R1 + R2 + R3 + R4 + R5 + R6 + R7 + R8 + R9)

= (3 - 6) / (22 + 33 + 1.1 + 3.3 + 33 + 11 + 33 + 1.1 + 3.3)

= -3 / 116.8

= -0.02563 A

Step-by-step explanation:

User Ihsan Fajar Ramadhan
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5.2k points
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