Question

What volume of solution is required to produce a 7.8M solution containing 23.6g of LiBr?

Answer 1

34.9 mL

Step-by-step explanation:

First we convert 23.6 g of LiBr into moles, using its molar mass (86.845 g/mol):

• 23.6 g ÷ 86.845 g/mol = 0.272 mol LiBr

Now we can calculate the required volume, using the definition of molarity:

• Molarity = moles / liters

• liters = moles / Molarity

• 0.272 mol / 7.8 M = 0.0349 L

We can convert L into mL:

• 0.0348 L * 1000 = 34.9 mL