Answer:
option D
Step-by-step explanation:
first quantum number of a 2s2
n = 2
second quantum number of a 2s2
l = 0 to n-1
l = 0, 1
For s orbital
l = 0
third quantum number of a 2s2
ml = - l to +l
ml = 0
fourth quantum number of a 2s2 electron be
?½ = spin down
½ = spin up
2s2 has 2 electrons 1 spin down and 1 spin up (starts with spin down)
ms = +1/2