Final answer:
To complete the recursive formula for the sequence g(n) = -72*(1/6)^(n-1), we can express g(n) in terms of its previous term, g(n-1), as g(n) = g(n-1) * (1/6).
Step-by-step explanation:
The given sequence is defined by the expression g(n) = -72*(1/6)^(n-1). To complete the recursive formula, we need to express g(n) in terms of its previous term, g(n-1). Let's start by finding g(n-1): g(n-1) = -72*(1/6)^(n-2). Now, we can express g(n) in terms of g(n-1): g(n) = -72*(1/6)^(n-1) = -72*(1/6)^((n-2)+1) = -72*(1/6)^(n-2) * (1/6) = g(n-1) * (1/6).