Answer:
25.8 L
Step-by-step explanation:
Step 1: Write the balanced equation for the complete combustion of acetylene
C₂H₂ + 2.5 O₂ ⇒ 2 CO₂ + H₂O
Step 2: Calculate the moles corresponding to 15.0 g of C₂H₂
The molar mass of C₂H₂ is 26.04 g/mol.
15.0 g × 1 mol/26.04 g = 0.576 mol
Step 3: Calculate the moles of CO₂ produced from 0.576 moles of C₂H₂
The molar ratio of C₂H₂ to CO₂ is 1:2. The moles of CO₂ produced are 2/1 × 0.576 mol = 1.15 mol.
Step 4: Calculate the volume corresponding to 1.15 moles of CO₂
At standard temperature and pressure, 1 mole of CO₂ occupies 22.4 L.
1.15 mol × 22.4 L/1 mol = 25.8 L