Question

Reacting Solutions of Aluminum Chloride with Potassium Hydroxide

Mixing the solutions of aluminum chloride and potassium hydroxide results in the following.

AlCl3(aq) + KOH(aq) --> KCl (aq) + Al(OH)3(s)

150 mL of a 1.50M aluminum chloride solution is mixed with 155 mL of a 2.50M potassium hydroxide solution and heated.

QUESTIONS:
1. Balance the equation: __AlCl3 + __KOH --> __KCl + __Al(OH)3
Write coefficients in order space between each number or a comma and a space for exam 1 2 3 4 or 1, 2, 3, 4

2. How many moles of aluminum chloride is needed to completely react with the given amount of potassium hydroxide?

A. 10.0 mol AlCl3
B. 0.225 mol AlCl3
C. 0.388 mol AlCl3
D. 0.129 mol AlCl3

3. How much aluminum hydroxide is made from this reaction? (reminder to leave space between number and unit)

Answer 1

the answer to ur question is A

Answer 2

1Al2(SO4)3 + 3ZnCl2 → 2AlCl3 + 3ZnSO4

The coefficients represents moles. There is 1 mole of Aluminum Sulfate, 3 moles of Zinc(II) Chloride, 2 moles of Aluminum Chloride, and 3 moles of Zinc(II) Sulfate.

Now add all the coefficients/moles.

9 is the sum of all the coefficients.