Question

You place air in a sealed can at standard temperature and pressure (STP). You double its absolute temperature (K) while leaving the

volume constant.
What happens to the pressure?

It doubles.
It decreases by one-half.
It increases to four times the original pressure.
It stays the same.

Answer 1

Pressure will double

Step-by-step explanation:

Gay - Lussac Law => P ∝ T with volume and mass held constant.

=> P₁/T₁ = P₂/T₂ => P₂ = P₁T₂/T₁

T₂ = 2T₁

P₂ = P₁(2T₁)/T₁ = 2P₁

Double absolute temperature => double pressure