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Find the surface area of a square pyramid with side length 5 cm and slant height 5 cm.

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Check the picture below.

so the four triangular faces of the pyramid each one has a base of 5 and a height of 5, and the squarish base is a 5x5, so let's just add those areas up.


\stackrel{\textit{\LARGE Areas}}{\stackrel{\textit{four triangles}}{4\left[\cfrac{1}{2}(\underset{b}{5})(\underset{h}{5}) \right]}~~ + ~~\stackrel{square}{(5)(5)}}\implies 50+25\implies \text{\LARGE 75}~cm^2

Find the surface area of a square pyramid with side length 5 cm and slant height 5 cm-example-1
User Quentin Skousen
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