Question

A space probe is launched vertically into space. It launches from rest and accelerates at a rate of 29 m/s^2. How many seconds before the probe reaches the speed required to get into orbit 7,850 m/s^2

Answer 1

Answer: 270

Step-by-step explanation:

To determine how many seconds it would take for a probe to reach that speed starting from rest and accelerating at a rate of 29 m/s^2, you can use the equation for average acceleration:

Average acceleration = (final velocity - initial velocity) / time

Rearranging the terms, we can solve for time:

Time = (final velocity - initial velocity) / average acceleration

In this case, the initial velocity is 0 m/s (since the probe is launching from rest), the final velocity is 7,850 m/s (the speed required to reach orbit), and the average acceleration is 29 m/s^2. Plugging these values into the equation, we get:

Time = (7850 m/s - 0 m/s) / 29 m/s^2 = 270.34 seconds

Therefore, it would take the probe approximately 270 seconds to reach the speed required to get into orbit if it is accelerating at a rate of 29 m/s^2.