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The sum of two numbers is 22. Three times one number increased by five is the same as twice the other number decreased by four. What is the LARGER of the two numbers? ​

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Answer: 15

Explanation:

To solve this problem, we first need to translate the given information into a system of equations. Let's call the first number x and the second number y. Since the sum of the two numbers is 22, we know that x + y = 22.

The second statement says that three times one number increased by five is the same as twice the other number decreased by four. We can translate this into an equation by substituting x and y for the two numbers and using the given information:

3x + 5 = 2y - 4

Now that we have a system of equations, we can solve for x and y. First, we'll solve for x by adding four to both sides of the second equation:

3x + 9 = 2y

Then, we can divide both sides by three to get the value of $x$:

x = {2y - 9} / {3}

Next, we can substitute this expression for x into the first equation to solve for y:

y + {2y - 9} / {3} = 22

We can simplify this equation by multiplying both sides by three:

3y + 2y - 9 = 66

Combining like terms on the left side, we get:

5y - 9 = 66

Then, we can add nine to both sides to solve for y:

5y = 75

Finally, we can divide both sides by five to find the value of y:

y = 15

Now that we know the value of $y$, we can substitute it back into the expression for $x$ to find the value of $x$:

x = \frac{2 \cdot 15 - 9}{3} = \frac{27}{3} = 9

Since we want the larger of the two numbers, the answer is 15

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