Answer:
Since MA ≠ TH, hence MATH is not a rectangle
Explanation:
To prove that quadrilateral MATH, M (-4,-1) A(-3,2). T(3,0), H(2-3) is a rectangle, we need to get the length of each sides and show that MA =TH and MH = TA
For MA:
M (-4,-1) A(-3,2)
MA = √(2+1)²+(3+4)²
MA = √(3)²+(7)²
MA = √9+49
MA =√58
For TH:
T(3,0), H(2-3)
TH = √(-3-0)²+(2-3)²
TH = √(-3)²+(-1)²
TH = √9+1
TH =√10
For TH:
M(-4,-1), H(2-3)
MH = √(-3+1)²+(2+4)²
MH = √(-2)²+(6)²
MH = √4+36
MH =√40
For TA:
T(3,0), A(-3,2)
TA = √(2-0)²+(-3-3)²
TA = √(2)²+(-6)²
TA = √4+36
TA =√40
Since MA ≠ TH, hence MATH is not a rectangle