Question

If an object that was held steady (0 speed) and then dropped, how many meters would it fall in one second?

Answer 1

h = 4.905 m

Step-by-step explanation:

In order to find the distance covered by the object in 1 second, we can use the second equation of motion:

`h = v_i t + (1)/(2)gt^2\\`

where,

h = distance covered = ?

vi = initial speed = 0 m/s

g = acceleration due to gravity = 9.81 m/s²

t = time = 1 s

Therefore,

`h = (0\ m/s)(1\ s)+(1)/(2)(9.81\ m/s^2)(1\ s)^2\\\\`

h = 4.905 m