Question

The volume of 3.2 moles of nitrogen gas inside a canister is 1.5L. The canister

volume is reduced to 0.3L. How many moles of nitrogen were released? ​

Answer 1

2.56 moles of nitrogen was released.

Step-by-step explanation:

We'll begin by calculating the final moles of nitrogen in the canister. This can be obtained as follow:

Initial mole (n₁) = 3.2 moles

Initial volume (V₁) = 1.5 L

Final volume (V₂) = 0.3 L

Final mole (n₂) =?

V₁/n₁ = V₂/n₂

1.5 / 3.2 = 0.3 / n₂

Cross multiply

1.5 × n₂ = 3.2 × 0.3

1.5 × n₂ = 0.96

Divide both side by 1.5

n₂ = 0.96 / 1.5

n₂ = 0.64 mole

Finally, we shall determine the number of mole of nitrogen that was released. This can be obtained as follow:

Initial mole (n₁) = 3.2 moles

Final mole (n₂) = 0.64 mole

Amount released =?

Amount released = n₁ – n₂

Amount released = 3.2 – 0.64

Amount released = 2.56 moles

Thus, 2.56 moles of nitrogen were released.