Answer:
2 3 4
Step-by-step explanation:
In the given program, the code inside the first if statement will be executed because the condition a < b is true. Since b is not less than c, the code inside the second if statement will not be executed, and the code inside the else clause of the second if statement will also not be executed. Therefore, the program will not print anything.
Here is a modified version of the program that will print the numbers in increasing order: public static void main(String[] args)
{
int a = 2;
int b = 3;
int c = 4;
if (a < b && b < c)
{
System.out.println(a + " " + b + " " + c);
}
else if (a < c && c < b)
{
System.out.println(a + " " + c + " " + b);
}
else if (b < a && a < c)
{
System.out.println(b + " " + a + " " + c);
}
else if (b < c && c < a)
{
System.out.println(b + " " + c + " " + a);
}
else if (c < a && a < b)
{
System.out.println(c + " " + a + " " + b);
}
else if (c < b && b < a)
{
System.out.println(c + " " + b + " " + a);
}
}
This modified program uses multiple if-else statements to check all possible orderings of the numbers a, b, and c. The first if statement checks if the numbers are in increasing order, and if so, it prints them in that order. The other if statements check the other possible orderings of the numbers and print them in increasing order if they are found. In the given case, where a is 2, b is 3, and c is 4, the first if statement will be executed and the program will print 2 3 4.