Question

C. 2.86 g

D. 1.22 g
13. At what Kelvin temperature will 25.2 mol of Xe occupy a volume of 645 L at a pressure of 732 torr?
A. 361 K
B. 291 K
C. 402 K
D. 300 K

Answer 1

The Kelvin temperature at which 25.2 mol of Xe occupies a volume of 645 L at a pressure of 732 torr is 291 K.

Step-by-step explanation:

To find the Kelvin temperature at which 25.2 mol of Xe occupies a volume of 645 L at a pressure of 732 torr, we can use the ideal gas law equation: PV = nRT. Rearranging the equation, we have T = PV / nR where P is the pressure in atm, V is the volume in liters, n is the number of moles, and R is the ideal gas constant (0.0821 atm·L/mol·K). Plugging in the values, we have T = (732 torr)(645 L) / (25.2 mol)(0.0821 atm·L/mol·K). Converting torr to atm and simplifying the equation, we get T = 291 K. Therefore, the correct answer is B. 291 K.