Question

3.

Balance the following reactions.
i)
Mg +
HCI →
MgCl2 +
H2
ii)
Mg(OH)2 +_
HCI →
MgCl2 +
H20
AgNO3 +
K3PO4 →
Ag3PO4 +
KNO3
iv)
H2SO4 +
Pb(OH)4 →
Pb(SO4)2 +
H2O
v)
Ca (OH)2 +
H3PO4 →
Ca3(PO4)2 +
H20​

Answer 1

Answer: i)
`Mg+2HCl\rightarrow MgCl_2+H_2`

ii)
`Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O`

iii)
`3AgNO_3+K_3PO_4\rightarrow Ag_3PO_4+3KNO_3`

iv)
`2H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+4H_2O`

v)
`3Ca(OH)_2+2H_3PO_4\rightarrow Ca_3(PO_4)_2+6H_2O`

Step-by-step explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical reactions will be:

i)
`Mg+2HCl\rightarrow MgCl_2+H_2`

ii)
`Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O`

iii)
`3AgNO_3+K_3PO_4\rightarrow Ag_3PO_4+3KNO_3`

iv)
`2H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+4H_2O`

v)
`3Ca(OH)_2+2H_3PO_4\rightarrow Ca_3(PO_4)_2+6H_2O`