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18 votes
The volumes of two bodies are measured to be

V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³. Calculate sum and difference in

volumes with error limits.​

User Dasnixon
by
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2 Answers

5 votes
5 votes

Answer:

I hope it's helpful .............

User Ivan Pereira
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17 votes
17 votes

Answer:

sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

Step-by-step explanation:

Here,

V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.

Now,

∆V = ± (∆V₁ + ∆V₂)

= ± (0.02 + 0.01) cm³

= ± 0.03 cm³

V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and

V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³

Thus, sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

-TheUnknownScientist

User BahaEddine Ayadi
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2.0k points