HELP MEEEEEEEEEEEEEEEEEEEEE PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

asked Jun 28, 2023 174k views

3 votes

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7 votes

Part a

Setting
x=6 ,
$y=7.9(1.02)^6 \approx \boxed{8.9}$

Part b

Setting
x=14 ,
$y=7.9(1.02)^(14) \approx \boxed{10.4}$

Afrosteve answered Jul 2, 2023

6.2k points

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