Question

A .Write an equation for the trend line in slope -intercept form .

Answer 1

Given:

The graph of a trend line.

To find:

The equation of the trend line is slope intercept form.

Solution:

From the given graph it is clear that the equation of the trend line is passes through the points (0,25) and (5,50).

Slope of the line is:

`m=(y_2-y_1)/(x_2-x_1)`

`m=(50-25)/(5-0)`

`m=(25)/(5)`

`m=5`

The line passes through the point (0,25). So, the y-intercept of the line is 25.

Slope intercept form of a line is:

`y=mx+b`

Where, m is slope and b is y-intercept.

The slope intercept from of the line is:

`y=(5)x+(25)`

`y=5x+25`

Therefore, the equation for the trend line in slope -intercept form is
`y=5x+25`.