Question

Solve for the variable in the following equation: 1 / 6c + 1 / 3 = - 2

A. c = −30

B. c = 26

C. c = −14

D. c = 12

Answer 1

C. c = −14

Explanation:

Combine multiplied terms into a single fraction

`(1)/(6) c+(1)/(3) = - 2`

`(1c)/(6) +(1)/(3) =-2`

Multiply by 1

`(1c)/(6) +(1)/(3) =-2`

`(c)/(6) +(1)/(3) =-2`

Subtract
`(1)/(3)` from both sides of the equation

`(c)/(6) +(1)/(3) =-2`

`(c)/(6) +(1)/(3) -(1)/(3) =-2-(1)/(3)`

Subtract the numbers

`(c)/(6) +(1)/(3) -(1)/(3) =-2-(1)/(3)`

`(c)/(6) =-2-(1)/(3)`

Subtract the numbers

`(c)/(6) =-2-(1)/(3)`

`(c)/(6) =-(7)/(3)`

Multiply all terms by the same value to eliminate fraction denominators

`(c)/(6) =-(7)/(3)`

`c (c)/(6) =6(-(7)/(3) )`

Cancel multiplied terms that are in the denominator

`c (c)/(6) =6(-(7)/(3) )`

c = 6
`(-(7)/(3) )`

Multiply the numbers

c = 6
`(-(7)/(3) )`

c = - 14

Answer 2

Answer: C. C=-14

Explanation:

Given

(1/6)c+1/3=-2

Multiply both sides by the LCM of 1/6 and 1/3(Least Common Multiple)

6[(1/6)c+1/3]=(-2)(6)

c+2=-12

Subtract 2 on both sides

c+2-2=-12-2

c=-14

Hope this helps!! :)

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