Question

Find all values of x for which the perimeter is at most 32​

Answer 1

0 < x ≤ 11

Explanation:

perimeter = (x - 6) + (x - 6) + x + x

⇒ perimeter = 4x - 12

If the perimeter is "at most 32" then

4x - 12 ≤ 32

⇒ 4x ≤ 44

⇒ x ≤ 11

Therefore, 0 < x ≤ 11